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# Transmission capacity

The table gives the required minimum hub diameter (Dhub) for various materials when the SH bushing is completely covered by the hub (fig 1).

## Designation example

Bushing with slotted outer components for 20 mm shaft = SHT 20.

## Width of hub smaller than bushing

If the width of the hub is smaller than L (fig 2), the hub diameter must be multiplied by the factor fk obtained from diagram 1.

## Example

SH bushing SHT 40
Hub material yield limit Rp 0,2 = 200 N/mm2
Hub width Lx = 31,5 mm
The required minimum hub diameter is obtained as follows:
Lx/L = 31,5/45= 0,7
From the diagram, fk = 1,18
Minimum hub diameter = Dhub fk = 89 × 1,18 = 105 mm

## Simultaneously acting torque and axial force

If the joint is simultaneously subjected to a torque and an axial force, the resultant torque is obtained using the equation:

MvR = √(Mv2 + (Pax d/2 000)2)

where

 MvR = maximum resultant torque [Nm] Mv = torque acting on bushing [Nm] Pax = axial force acting on bushing [N] d = shaft diameter, mm

## Example

Bushing SHT 50 is subject to an axial force of 20 000 N and simultaneously to a torque of 500 Nm. The machine factor fd is estimated as being 1,5.
MvR = √(5002 + (20 000 × 50/2 000)2) = 707 Nm
According to the table, the maximum torque for SHT 50 is 1 625 Nm. The permissible torque is then:
1 625/1,5 = 1 083 Nm